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wRog
more on S4 (really A5, but who cares) 
26th-Nov-2006 03:46 am
toyz
So I guess that was too easy.

But yes, as people figured out, orientation matters.

And if you roll the die into a crease, preferably one that's bent at exactly a 90o angle so the die can't rattle around -- or alternatively, use a gamebox lid that's been propped up -- then you don't have to do any pushing, measuring, or other extra work. The die just lands in one of 24 ways (12 edges x 2 orientations) and that's it.

The rest is a matter of arranging things so that you can read off an answer quickly -- preferably in a manner such that the less-math-inclined folks could be immediately convinced of the fairness of the process (*). So far, the best answer seems to be to use 4 colors to paint each pair of opposite corners of the cube -- or at least to imagine things this way if the frogs won't let you paint anything. Then you just say "uppermost north corner wins" (i.e., if your crease is running north-south) to get your choice of 4.

And if you need a permutation of 4, then it's "north face, start at the top corner, go counterclockwise" and read off the colors. This works because the 24 rotations of the cube give you all possible permutations of the body-diagonal axes (the group-theory wonks would say, "the group of rotation symmetries of the cube is isomorphic to S4, the permutation group on 4 elements").

(*) I suppose what got me on to this was the is the whole question of what's the simplest device you can carry around with you that can easily accomplish the widest variety of everyday randomization tasks (**); call it the Economical D&D Problem (i.e., how to play with just one die because you're too lame to go out and buy a full set, and how to mark it and otherwise set things up so that using it isn't too painful).

I figure specially marked cubical die + box lid gives you d2,d3,d4,d6,d8,d12,d24 and permutations of 3 or 4, pretty much instantly.

The next step is to realize that dodecahedral (12-sided) or icosahedral (20-sided) dice are likely to be better for this sort of thing if you think factors of 5 are likely to come up.

The rotation-symmetry group of the dodecahedron has 60 elements (30 edges to land on, 2 orientations for each; or 12 faces times 5 rotations each; or 20 vertices times 3 rotations each), and hence if it's marked in the right way, you can do all of d2,d3,d4,d5,d6,d10,d12,d15,d20,d30, and d60. It also happens that this group is isomorphic to A5, the group of even permutations on 5 elements (i.e., ones you can do with an even number of swaps), you can't get to the odd permutations unless you're willing to do an extra coin toss -- either that or we need to contrive a way to throw the dodecahedron through 4-dimensional space so that a "roll" can do parity inversions as well,... but let's not go there.

The icosahedron is essentially the same in that you have the same symmetry group as the dodecahedron -- where you were swapping faces before, now you're swapping vertices, and vice versa... so exactly the same set of rotations work for each. Though there are other issues; icosahedron has more places to put potentially useful labels (if one decrees that each face can only have one) and, finally, it rolls differently.

At this point I get to flame the D&D folks for not considering more carefully the markings for their 12&20-sided dice before launching the mass-production machinery. The result is that there are lots of stupidly (or at least, non-optimally) marked dice out there.

(On the other hand, I suppose it's a plus that these things are so ubiquitous that I don't have to explain "12-sided" and "20-sided" dice to people).

Really, for numbering an icosahedron, you want something like this (caution: half-assed stereographic projection follows):
The cool thing here is if some random process designates a face and a vertex, then you can read counterclockwise around the vertex starting from the face to get an even 5-permutation (which you can then reduce to anything else you want in the d2,d3,d4,d5,etc. list). I'll grant I'm still waffling on the most useful vertex coloring.

(... and wow do we need to get SVG adoped everywhere or something so I don't have to do these crappy conversions to .png anymore)

Various flies in the ointment for the icosahedron/dodecahedron
  • you don't get d8 or d24
  • you only get even permutations (i.e., you need that extra coin toss if you want all of them. buh).
  • a 90o crease doesn't work anymore since you need something that's an angle between a pair of faces of the object
That last one is interesting since it does not have to be an angle between adjacent faces, and in fact it's better if it's not. The farther apart the faces, the narrower the angle, the more vertical the sides of the crease, and thus the greater the role for gravity vs. friction, which then pulls the die into the right orientation much more quickly.

The most extreme case is the icosahedron being tossed into a 41.8o crease; it makes a nice, satisfying "THOCK". No long wait for it to stop rolling or anything. 41.8o being arccos(sqrt(5)/3) is fairly easy to construct, too, but you actually don't need to bother since any smaller angle works just as well -- instead of resting on two faces, the die hangs by a pair of parallel opposing edges that are fairly long with respect to the diameter (or at least longer than the corresponding edges for the dodecahedron), making things nice and stable. So all you really have to do is eyeball some angle roughly 40o or smaller and you're done. So even though you can't use the readily available boxlids anymore, it's all still quite doable.

(**) and no, I have no idea what might have gotten me onto the question of how to randomly order nominees making speeches for a given office. Yeah I know, in real life, everybody just draws straws, but ugh.

Deck of cards works, too, I suppose. Though you may have to convince people it's not stacked...
Comments 
26th-Nov-2006 01:53 pm (UTC)
For the cube problem, I was thinking you could color edges, not corners, to get your d4. I didn't come up with the idea of tossing it into a box corner, but if you'd color edges you'd have a clear winner and wouldn't need to specify "upper north corner" or whatever.

(This was prompted by musing on the fact that the d8 and d6 are dual.)
27th-Nov-2006 02:18 am (UTC) - Re: stacked deck
my original solution for d4 was to take the top two numbers and subtract. It almost works; it's just that if you see a 2 and no 6, then you have to pretend the 2 is a 0 in order for the odds to work out. Which then has to be explained and bleah.

I guess this is the winner, then
                a
      4        /
        .__d__.
       / \     \
      c   b  1  c
     /     \     \
__b_.   2   .__a__. 5
     \     /     /
      a   d  3  b
       \ /     /
        .__c__.
     6         \
                d
(upper faces hi-lo/lo-hi or upper edge ac|bd (or ab|cd) for d2, smallest side face for d3, upper edge for d4, left side for d6, upper edge + hi-lo for d8, upper edge + next clockwise for 4-choose-2,... whee)
26th-Nov-2006 04:17 pm (UTC) - stacked deck
Yeah, like I'm not gonna think that some guy walking around with a re-marked D12 might not have bothered to jigger it a bit on the way. Fat chance.

I think another interesting question is:
How do you acomplish all these tasks with an economy of random events, and how do you generate random events. Coins are pretty available. Pencils work for D6. Are there other sitting-around Dxs?
26th-Nov-2006 09:00 pm (UTC) - Re: stacked deck
For powers of 2 I like multiple coins and binary, but it turns out the average person doesn't understand that, even with an explanation, and is likely to think you're making it up as you go. As I found out when I did a 'raffle' on a tatting mailing list once, and got 64 replies. I told them I'd pulled out 8 pennies and used binary and it was a big huge "whaaa?"
26th-Nov-2006 10:27 pm (UTC) - Re: stacked deck
they were probably confused because everyone knows you only need 6 pennies to do 64
26th-Nov-2006 10:33 pm (UTC) - Re: stacked deck
Yes, right, six. Shh. I hadn't had any tea yet.
27th-Nov-2006 02:58 am (UTC) - Re: stacked deck
Re pencils:
I'm not sure they work all that hard on getting pencils to be actually hexagonal -- I seem to recall seeing lots of pencils with alternating flat and rounded sides. (I also seem to use far fewer pencils these days; pen seems to be just fine if I don't have an emacs buffer in front of me...)

Re jiggered dice:
That's why having these things mass-produced would be a big win (i.e., if one can get the mass-producers to adopt the right labelling...).

One can also reduce the efficacy of loaded dice by getting people to call it in the air ("Andy, roll the die; Bob, pick a color; Carol, pick clockwise or counterclockwise;...")

Which then leads to the various rock-paper-scissors style games where you don't need any randomization device at all
27th-Nov-2006 07:18 am (UTC) - Re: stacked deck
People are really bad randomizers. If we play "call it in the air" I'd far rather have a two-tailed coin than a two-headed one.

Oh, and lots of people have a pretty good D60 on their wrist, and it sometimes has a pretty good D100, too.
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